Q35 Longest Repeating Subsequence | Practice | GeeksforGeeks

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Mon Mar 27 2023 04:52:34 GMT+0000 (Coordinated Universal Time)

Saved by @Ayush_dabas07

//{ Driver Code Starts
//Initial Template for Java

import java.util.*;
import java.lang.*;
import java.io.*;
class GFG
{
    public static void main(String[] args) throws IOException
    {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        int T = Integer.parseInt(br.readLine().trim());
        while(T-->0)
        {
            String str = br.readLine().trim();
            Solution ob = new Solution();
            int ans = ob.LongestRepeatingSubsequence(str);
            System.out.println(ans);
        }
    }
}

// } Driver Code Ends


//User function Template for Java

class Solution
{
    public int LongestRepeatingSubsequence(String str)
    {   
        /* Q35 dp playlist , finding Longest common subsequence in str with itself ,
        and checking if equal characters have equal indexes or not as we need to find
        repeated string with different characters
        */
        int n = str.length() ;
        
        int[][] dp = new int[n+1][n+1];
        
        //last row ,last coloumn  and last cell will be 0 by default
        //handling for rest of the dp
        for(int i = n-1 ; i>=0 ; i--){
            
            for(int j = n-1 ; j>=0 ; j--){
                
                //checking if chars are equal and indexes are not
                if(str.charAt(i) == str.charAt(j) && i!=j)
                    dp[i][j] = dp[i+1][j+1] + 1;
            
                else
                    dp[i][j] = Math.max(dp[i][j+1] , dp[i+1][j]);
            
            }
        }
        
        return dp[0][0];
    }
}

https://practice.geeksforgeeks.org/problems/longest-repeating-subsequence2004/1

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