double a battery voltage - Google Search

Tue Nov 14 2023 02:40:52 GMT+0000 (Coordinated Universal Time)

Saved by @daniel1000

#include <LiquidCrystal.h> const int butpin = 8; int bState = HIGH; int lbState = HIGH; unsigned long lastDebounceTime = 0; unsigned long debounceDelay = 50; const int rs = 12, en = 11, d4 = 5, d5 = 4, d6 = 3, d7 = 2; LiquidCrystal lcd(rs, en, d4, d5, d6, d7); int butVal; int stepCounter = 0; const int bp = A0; int bVal; float volts; void setup() { lcd.begin(16, 2); pinMode(butpin, INPUT); Serial.begin(9600); } void loop() { butVal = digitalRead(butpin); bVal = analogRead(bp); volts = bVal * (5.0 / 1023); if(butVal != lbState){ lastDebounceTime = millis(); } if((millis() - lastDebounceTime) > debounceDelay){ if(butVal != bState){ bState = butVal; if(bState == HIGH){ stepCounter++; } } } lbState = butVal; lcd.setCursor(0,0); lcd.print("Steps: "); lcd.print(stepCounter); lcd.setCursor(0, 1); lcd.print("GenEnergy: "); lcd.print(volts); lcd.print("v"); Serial.println(butVal); }