a given array ,multiple index odd ,with 2 and index even increment of 10;print new array

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Mon Feb 10 2025 18:43:39 GMT+0000 (Coordinated Universal Time)

Saved by @meherbansingh

#include <iostream>
using namespace std;

int main() 
{
    
    int arr[]={1,2,3,4,5,6};
    for (int i = 0; i < 6; i++) {
        if (arr[i]%2==0){
          arr[i]=arr[i]+10;
        }
        else arr[i]=arr[i]*2;
         cout<<arr[i]<<" ";
    }
    
    return 0;
}
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