6th linud

Write a shell script that accepts any number of arguments and prints them in the reverse 

order.

Script:

a=$#

echo "Number of arguments are" $a

x=$*

c=$a

res=''

while [ 1 -le $c ]

do

c=`expr $c - 1`

shift $c

res=$res' '$1

set $x

done

echo Arguments in reverse order $res

Output:

sh 1prg.sh a b c

No of arguments are 3

Arguments in reverse order c b a