JavaScript Coding Challenge #1. Multiples of 3 and 5 | by Florin Pop | Medium

function sumOfMultiples(number) {
    let sum = 0;
    for(let i=1; i<number; i++) {
        if(i % 3 === 0 || i % 5 === 0){
            sum += i;
        }
    }
    return sum;
}