Largest Local Values in a Matrix

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Sun May 19 2024 19:20:00 GMT+0000 (Coordinated Universal Time)

var largestLocal = function (grid) {
    let rowLen = grid.length, colLen = grid[0].length
    console.log(rowLen, colLen)
    let mainArr = []
    for (let init = 0; rowLen - init > 2; init++) {
        let childArr = []
        let tem = 0
        for (let col = tem; rowLen - col > 2; col++) {
            let container = []
            for (let sub = init; sub < 3; sub++) {
                let sumTemp = grid[sub].slice(col, 3);
                console.log("sumTemp at ", sub, " is ", sumTemp)
                container.push(...sumTemp)
                console.log("container at ", sub, " is ", container)
            }
            let max = Math.max(...container);
            console.log("max at ", col, " is ", max)
            childArr.push(max)
            console.log("childArr at ", col, " is ", childArr)

        }
        mainArr.push([...childArr])
    }
    return mainArr
};

COPY

You are given an n x n integer matrix grid. Generate an integer matrix maxLocal of size (n - 2) x (n - 2) such that: maxLocal[i][j] is equal to the largest value of the 3 x 3 matrix in grid centered around row i + 1 and column j + 1. In other words, we want to find the largest value in every contiguous 3 x 3 matrix in grid. Input: grid = [[9,9,8,1],[5,6,2,6],[8,2,6,4],[6,2,2,2]] Output: [[9,9],[8,6]] Explanation: The diagram above shows the original matrix and the generated matrix. Notice that each value in the generated matrix corresponds to the largest value of a contiguous 3 x 3 matrix in grid. Input: grid = [[1,1,1,1,1],[1,1,1,1,1],[1,1,2,1,1],[1,1,1,1,1],[1,1,1,1,1]] Output: [[2,2,2],[2,2,2],[2,2,2]] Explanation: Notice that the 2 is contained within every contiguous 3 x 3 matrix in grid. Constraints: n == grid.length == grid[i].length 3 <= n <= 100 1 <= grid[i][j] <= 100

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Largest Local Values in a Matrix

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