select id, name from table 
where name ilike all(string_to_array(replace('%'||TRIM('JOHN DOE')||'%',' ','%,%'), ','))

-- 1) it converts spaces into commas (,)
-- 2) it converts string to array using resulting comma separated string
-- 3) it apply ilike to each word in search string

-- It finds (for example) name = 'DOE, JHON'  in table
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