Preview:
public boolean isAnagram(String s, String t) {
  if (s.length() != t.length()) {
    return false;
  }
  
  int[] count = new int[26];
  
  for (int i = 0; i < s.length(); i++) {
    count[s.charAt(i) - 'a']++;
    count[t.charAt(i) - 'a']--;
  } 
  
  for (int c : count) {
    if (c != 0) {
      return false;
    }
  }
  
  return true;
}
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