Q31 Subarray Sums Divisible by K - LeetCode

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Thu Jan 26 2023 21:21:50 GMT+0000 (Coordinated Universal Time)

Saved by @Ayush_dabas07

class Solution {
    public int subarraysDivByK(int[] arr, int k) {
//make a HM<remainder,frequency of remainder > , traverse and make PSA and keep storing remainders
//if any remainder repeats then subarray between them will be divisible of k 
// add frequency of rem to answer and then add rem itself 
        HashMap<Integer, Integer> map = new HashMap<>();
        int psa = 0 , ans = 0 ;
        map.put(0 , 1);
        
        for(int i =0 ;i < arr.length ; i++){
            int val = arr[i];
            psa += val;
            
            //find remainder
            int rem = psa%k;
            
            //if remainder comes out to be -ve add k
            if(rem < 0) rem += k;
            
            if(map.containsKey(rem)){
                ans += map.get(rem);
            }
            
                map.put(rem , map.getOrDefault(rem,0)+1);
            
        }

        return ans;
    }
}

https://leetcode.com/problems/subarray-sums-divisible-by-k/

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