Print a pattern for given integer. First reduce 5 one by one until we reach a negative or 0. After we reach 0 or negative, we add 5 until we reach n. Input : 16 Output : 16 11 6 1 -4 1 6 11 16 || Input : 20 Output : 20 15 10 5 0 5 10 15 20

PHOTO EMBED

Thu Feb 06 2025 04:53:37 GMT+0000 (Coordinated Universal Time)

Saved by @Rohan@99

#include <iostream>
using namespace std;

int initialValue;

void IncreaseNumber(int n){
  if(n == initialValue){
    return;
  }
  
  n += 5;
  cout << n << " ";
  IncreaseNumber(n);
}

void DecreaseNumber(int n){
  if(n <= 0){
    cout << n << " ";
    IncreaseNumber(n);
    return;
  }
  
  cout << n << " ";
  n -= 5;
  DecreaseNumber(n);
}

int main() {
    cin >> initialValue;
    
    DecreaseNumber(initialValue);

    return 0;
}
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