(Display the ASCII character table) Write a program that prints all the uppercase characters of the ASCII character table. Display 5 characters per line. The ASCII table is shown in Appendix B. Characters are separated by exactly one space.

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Sat Oct 24 2020 02:47:16 GMT+0000 (UTC)

Saved by @mahmoud hussein #c++

#include <iostream>
#include<cmath>
#include<ctime>
#include<string>
#include <iomanip>
#include <fstream>

using namespace std;

int main()
{
	int firstLetter = 65;
	int count = 0;

	for (int i = 65; i <= 90; i++)
	{
		count++;
		if (count%5 == 0)
			cout << setw(3) << static_cast<char>(i) << endl;
		else
			cout << setw(3) << static_cast<char>(i);

		
		
	}

	
	
		

	
	
}

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#include<iostream>
using namespace std;
bool issafe(int** arr,int x,int y,int n){
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        if(arr[x][y]==1){
            return false;
        }
    }
    int row=x;
    int col=y;
    while(row>=0 && col>=0){
        if(arr[row][col]==1){
            return false;
        }
        row--;
        col--;
    }
     row=x;
     col=y;
    while(row>=0 && col<n){
        if(arr[row][col]==1){
            return false;
        }
        row--;
        col++;
    }
    return true ;
}
bool nqueen(int** arr,int x,int n){
    if(x>=n){
        return true;
    }
    for(int col=0;col<=n;col++){
        if(issafe(arr,x,col,n)){
            arr[x][col]==1;
            if(nqueen(arr,x+1,n)){
                return true;
            }
            arr[x][col]=0;  //backtracking
            
        }
    }
    return false;
}
int main(){
    int n;
    cin>>n;
    int** arr=new int*[n];
    for(int i=0;i<n;i++){
        arr[i]=new int[n];
        for(int j=0;j<n;j++){
            arr[i][j]=0;

        }
    }
    if(nqueen(arr,0,n)){
        for(int i=0;i<n;i++){
            for(int j=0;j<n;j++){
                cout<<arr[i][j]<<"";
            }cout<<endl;
        }
    }


    return 0;
}

**8.11 (Game: nine heads and tails)

#include <iostream>
#include<cmath>
#include<ctime>
#include<string>
#include <iomanip>
#include <fstream>

using namespace std;




void decToBinary(int n)
{
    // array to store binary number 
    int binaryNum[3][3];
    
    //converting to binary 
    for (int i = 0; i < 3; i++) 
    {
        for (int j = 0; j < 3; j++)
        {
            binaryNum[i][j] = n % 2;
            n = n / 2;

        }
     }       

    // printing binary> array in reverse order 
    for (int i = 3-1; i >= 0; i--){
        for (int j = 3 - 1; j >= 0; j--)
        {
            if (binaryNum[i][j] == 0)
                cout << "H" << " ";
            else
                cout << "T" << " ";
        }
        cout << endl;
    }
    
 }

int main()
{
    int n;
    cout << "Enter a decimal number between 1 and 512 ";
    cin >> n;

    decToBinary(n);
    return 0;
}

#include<iostream>
using namespace std;

int sum(int arr[], int a);

int main() {
    int arr[1000], n;
    cin >> n;
    for (int i = 0; i < n; ++i) {
        cin >> arr[i];
        cout << sum(arr, n);
    }
}
int sum(int arr[], int a) {
    int i;
    sum = 0;
    for (i=0; i<n; ++i) {
        sum += arr[i];
    }
    return sum;
}#include<iostream>
using namespace std;

int sum(int arr[], int a);

int main() {
    int arr[1000], n;
    cin >> n;
    for (int i = 0; i < n; ++i) {
        cin >> arr[i];
        cout << sum(arr, n);
    }
}
int sum(int arr[], int a) {
    int i;
    sum = 0;
    for (i=0; i<n; ++i) {
        sum += arr[i];
    }
    return sum;
}

(Display calendars) Write a program that prompts the user to enter the year and first day of the year and displays the calendar table for the year on the console. For example, if the user entered the year 2013 and 2 for Tuesday, January 1, 2013, your program should display the calendar for each month in the year, as follows:

#include <iostream>
#include<cmath>
#include<ctime>
#include<string>
#include <iomanip>
#include <fstream>

using namespace std;

int main()
{
	cout << "enter the year ";
	int year;
	cin >> year;
	
	cout << "Enter The First Day Of The year ";
	int FirstDay;
	cin >> FirstDay;
	int count = 1;
	int days = 1;
	for (int month = 1; month <= 12; month++)
	{
		cout << "             ";
		switch (month)
		{
		case 1: cout << "January " << year<<endl;
			break;
		case 2: cout << "February " << year << endl;
			break;
		case 3: cout << "March  " << year << endl;
			break;
		case 4: cout << "April  " << year << endl;
			break;
		case 5: cout << "May " << year << endl;
			break;
		case 6: cout << "June  " << year << endl;
			break;
		case 7: cout << "July  " << year << endl;
			break;
		case 8: cout << "August " << year << endl;
			break;
		case 9: cout << "September " << year << endl;
			break;
		case 10: cout << "October " << year << endl;
			break;
		case 11: cout << "November " << year << endl;
			break;
		case 12: cout << "December " << year << endl;
			break;
		}
		cout << " --------------------------------------------------------- "<<endl;
		cout << "  Sun Mon Tue Wed Thu Fri Sat"<<endl;
		for (int i = 0; i < FirstDay; i++)
		{
			cout << "    ";
		}
		for (int i = 1; i < 31; i++)
		{
			if (i < 10) {
				cout<<"   " <<i;
			}
			else {
				cout<<"  " << i;
			}
			if ((i + FirstDay) % 7 == 0) {
				cout << endl;
			}
		}
		cout << endl;

		FirstDay = (FirstDay + 31) % 7;
		
	}
	
	
}

(Display the Sundays in a month) Write a program that prompts the user to enter the month and first day of the month, and displays all the Sundays in that month. For example, if the user entered the month 7 for July, and the first day 4 for Wednesday, your program should display the following output: The first day of this month is Wednesday! ... Next Sunday of this month is on 26

#include <iostream>
#include<cmath>
#include<ctime>
#include<string>
#include <iomanip>
#include <fstream>

using namespace std;

int main()
{
	cout << "enter the month ";
	int month;
	cin >> month;
	cout << "Enter The First Day Of The Month ";
	int firstDay;
	cin >> firstDay;
	int nextSunday = 1;
	
		switch (firstDay)
		{
			
		case 1: nextSunday += 7;
			cout << "The first day of this month is sunday "<<endl;
			while (nextSunday < 30)
			{
					cout << "Next Sunday of this month is on " << nextSunday << endl;
									nextSunday += 7 ;
			}
			break;

		case 2: nextSunday += 6;
			cout << "The first day of this month is monday " << endl;
			while (nextSunday < 30)
			{
				cout << "Next Sunday of this month is on " << nextSunday << endl;
				nextSunday += 7;
			}
			break;
		case 3: nextSunday += 5;
			cout << "The first day of this month is tuesday " << endl;
			while (nextSunday < 30)
			{
				cout << "Next Sunday of this month is on " << nextSunday << endl;
				nextSunday += 7;
			}
			break;
		case 4: nextSunday += 4;
			cout << "The first day of this month is wednesday " << endl;
			while (nextSunday < 30)
			{
				cout << "Next Sunday of this month is on " << nextSunday << endl;
				nextSunday += 7;
			}
			break;
		case 5: nextSunday += 3;
			cout << "The first dayof this month is thursday " << endl;
			while (nextSunday < 30)
			{
				cout << "Next Sunday of this month is on " << nextSunday << endl;
				nextSunday += 7;
			}
			break;
		case 6: nextSunday += 2;
			cout << "The first day of this month is friday " << endl;
			while (nextSunday < 30)
			{
				cout << "Next Sunday of this month is on " << nextSunday << endl;
				nextSunday += 7;
			}
			break;
		case 7: nextSunday += 1;
			cout << "The first day of this month is saturday " << endl;
			while (nextSunday < 30)
			{
				cout << "Next Sunday of this month is on " << nextSunday << endl;
				nextSunday += 7;
			}
			break;

		}
		
}

#c++ #algorithms #interviewquestions #arrays

Kadane’s Algorithm

int maxSubArraySum(int a[], int size) 
{ 
int max_so_far = 0, max_ending_here = 0; 
for (int i = 0; i < size; i++) 
{ 
	max_ending_here = max_ending_here + a[i]; 
	if (max_ending_here < 0) 
		max_ending_here = 0; 

	/* Do not compare for all elements. Compare only 
		when max_ending_here > 0 */
	else if (max_so_far < max_ending_here) 
		max_so_far = max_ending_here; 
} 
return max_so_far; 
}

Reverse a linked list

#include<bits/stdc++.h>
 
using namespace std;
 
struct node {
    int data;
    struct node *next;
};
 
// To create a demo we have to construct a linked list and this 
// function is to push the elements to the list. 
void push(struct node **head_ref, int data) {
    struct node *node;
    node = (struct node*)malloc(sizeof(struct node));
    node->data = data;
    node->next = (*head_ref);
    (*head_ref) = node;
}
 
// Function to reverse the list
void reverse(struct node **head_ref) {
    struct node *temp = NULL;
    struct node *prev = NULL;
    struct node *current = (*head_ref);
    while(current != NULL) {
        temp = current->next;
        current->next = prev;
        prev = current;
        current = temp;
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    (*head_ref) = prev;
}
 
// To check our program 
void printnodes(struct node *head) {
    while(head != NULL) {
        cout<<head->data<<" ";
        head = head->next;
    }
}
 
// Driver function
int main() {
    struct node *head = NULL;
    push(&head, 0);
    push(&head, 1);
    push(&head, 8);
    push(&head, 0);
    push(&head, 4);
    push(&head, 10);
    cout << "Linked List Before Reversing" << endl;
    printnodes(head);
    reverse(&head);
    cout << endl;
    cout << "Linked List After Reversing"<<endl;
    printnodes(head);
    return 0;
}

Сетевой Город. Образование. Дневник

https://sgo.tomedu.ru/angular/school/studentdiary/

rdtsc intrinsics

// rdtsc.cpp
// processor: x86, x64
#include <stdio.h>
#include <intrin.h>

#pragma intrinsic(__rdtsc)

int main()
{
    unsigned __int64 i;
    i = __rdtsc();
    printf_s("%I64d ticks\n", i);
}

Boilerplate cpp

{
	// Place your snippets for cpp here. Each snippet is defined under a snippet name and has a prefix, body and 
	// description. The prefix is what is used to trigger the snippet and the body will be expanded and inserted. Possible variables are:
	// $1, $2 for tab stops, $0 for the final cursor position, and ${1:label}, ${2:another} for placeholders. Placeholders with the 
	// same ids are connected.
	// Example:
	"Print to console": {
		"prefix": "cpp boilerplate",
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			"#define pb(a) push_back(a)",
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			"#define array(n,name) ll int *name=new ll int[n]",
			"#define Zubin ios::sync_with_stdio(false);",
			"#define Shah cin.tie(NULL);cout.tie(0);",
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Kth element of Spiral Traversal

	public:
	int findK(vector<vector<int>> &a, int n, int m, int k)
    {
        // 1 2 3 4 5 
        // 6 7 8 9 10
        //11 12 13 14 15
        //16 17 18 19 20
        //21 22 23 24 25
        // k=4
        // 1 2 3
        // 4 5 6
        // 7 8 9
        // Your code goes here
        // if(k==1) return a[0][0];
        int lrow=0;
        int lcol=0;
        int urow=n-1;
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        int i=0,j=0;
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                    goto x;
                }
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            j--;
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            for(i=lrow+1;i<=urow;i++){
                // cout<<"i:"<<i<<"j:"<<j<<endl;
                count++;
                if(count==k) {
                    goto x;
                }
                
            }
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            i--;
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            for(j=ucol;j>=lcol;j--){
                // cout<<"i:"<<i<<"j:"<<j<<endl;
                count++;
                if(count==k) {
                    goto x;
                }
                
            }
            lcol++;
            j++;
            //iterating from down to up
             for(i=urow;i>=lrow+1;i--){
                //  cout<<"i:"<<i<<"j:"<<j<<endl;
                count++;
                if(count==k) {
            // cout<<"lrow:"<<lrow<<" urow:"<<urow<<" lcol:"<<lcol<<" ucol:"<<ucol<<endl;
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            lrow++;
            i++;
            
        }
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class Solution {
public:
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                q = (q + 1) % m;
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            }
        }
        return ans;
    }
};

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class Solution {
public:
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        return ans;
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};

// we can use auxilary array and store maxSoFar value

350. Intersection of Two Arrays II (Leetcode)

class Solution {
public:
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        }
        return ans;
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};

167. Two Sum II - Input array is sorted (Leetcode)

class Solution {
public:
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};

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