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// Efficient Code
 
import java.util.*;
import java.io.*;

class GFG 
{ 
	static int bSearch(int arr[], int low, int high, int x)
	{
		if(low > high)
			return -1;

		int mid = (low + high) / 2;

		if(arr[mid] == x)
			return mid;

		else if(arr[mid] > x)
			return bSearch(arr, low, mid - 1, x);

		else
			return bSearch(arr, mid + 1, high, x);
	}

	static int search(int arr[], int x)
	{
		if(arr[0] == x) return 0;

		int i = 1;

		while(arr[i] < x)
			i = i * 2;

		if(arr[i] == x) return i;

		return bSearch(arr, i / 2 + 1, i - 1, x);
	}

	public static void main(String args[]) 
    {
		int arr[] = {1, 2, 3, 40, 50};

		int x = 4;

        System.out.println(search(arr, x));     // OUTPUT : -1
    } 

}
 
 
 
 
 
// Naive Code
 
import java.util.*;
import java.io.*;

class GFG 
{ 
	static int search(int arr[], int x)
	{
		int i = 0;

		while(true)
		{
			if(arr[i] == x) return i;

			if(arr[i] > x) return -1;

			i++;
		}
	}

	public static void main(String args[]) 
    {
		int arr[] = {1, 2, 3, 5, 5};

		int x = 4;

		System.out.println(search(arr, x));     // OUTPUT : -1
    } 

}
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Tue Feb 08 2022 13:47:36 GMT+0000 (Coordinated Universal Time)

#java #gfg #geeksforgeeks #lecture #searching #infinitearray

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