Tree: is subtree of another tree DFS recursive with helper Python

PHOTO EMBED

Mon Jul 18 2022 23:05:55 GMT+0000 (Coordinated Universal Time)

Saved by @bryantirawan #python #tree #recursion #dfs #neetcode

# Definition for a binary tree node.
# class TreeNode:
#     def __init__(self, val=0, left=None, right=None):
#         self.val = val
#         self.left = left
#         self.right = right
class Solution:
    def isSubtree(self, root: Optional[TreeNode], subRoot: Optional[TreeNode]) -> bool:
        #order of first two conditionals is important 
        if not subRoot: return True 
        if not root: return False 
        if self.sameTree(root, subRoot): return True 
        
        return self.isSubtree(root.left, subRoot) or self.isSubtree(root.right, subRoot)
        
        
    def sameTree(self, s, t): 
        if not s and not t: return True 
        if s and t and s.val == t.val: 
            return self.sameTree(s.left, t.left) and self.sameTree(s.right, t.right) 

        return False 
        
        
content_copyCOPY