Q50 - Distinct Transformation- LeetCode Playground ( recursion + memoization approach)

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Fri Mar 31 2023 11:32:12 GMT+0000 (Coordinated Universal Time)

Saved by @Ayush_dabas07

import static java.lang.Math.max;
import static java.lang.Math.min;
import static java.lang.Math.abs;
import static java.lang.System.out;
import java.util.*;
import java.io.*;
import java.math.*;

public class main {
    
    public static int solution(String s1 , String s2 , int si ,int ti , int[][] dp){
        //base case if target ends
        if(ti == s2.length())
            return 1;
        
        //if source string ends
        else if(si == s1.length())
            return 0;
        
        //memoization , if answer is already calculated return it
        if(dp[si][ti] != -1)
            return dp[si][ti];
        
        //taking out characters
        char ch1 = s1.charAt(si) , ch2 = s2.charAt(ti);
        
        int totalways = 0;
        //if chars are not equal we delete source character and give a call
        if(ch1 != ch2)
            totalways = solution(s1 , s2 , si+1 , ti , dp);
        
        //if chars are equal we give 2 calls 1 with both matching other with removing
        //only source character
        else{
            int tw1 = solution(s1,s2,si+1,ti+1,dp);
            int tw2 = solution(s1,s2,si+1,ti,dp);
            
            totalways = tw1 + tw2;
        }
        
        dp[si][ti] = totalways;
        
        return totalways;
    }
    public static void main(String[] args) throws Exception {   
         Scanner scn = new Scanner(System.in);
        String s1 = scn.next();
        String s2 = scn.next();
        
        int[][] dp = new int[s1.length()][s2.length()];
        
        for(int i = 0 ; i < dp.length ; i++){
            for(int j = 0 ; j < dp[0].length ; j++)
                dp[i][j] = -1;
        }
        
        System.out.println(solution(s1, s2 , 0 ,0 , dp));
    }
}

https://leetcode.com/playground/2nCsfjag

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DP level 2

@Ayush_dabas07

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