Q62 Super Ugly Number - LeetCode 313

PHOTO

Sun Apr 02 2023 09:30:49 GMT+0000 (Coordinated Universal Time)

Saved by @Ayush_dabas07

class Solution {
    public int nthSuperUglyNumber(int n, int[] primes) {
        /* Q62 of dp playlist , every cell denotes ith ugly number . here we make
        a pointers array to store pointer for all factors which are in primes 
        array. rest same approach as ugly numbers.

        we apply 2 loops 1-> to check the minimum of all values given by factors
        and 2-> to update the indexes of pointers
        */
        int m = primes.length;
        
        long[] dp = new long[n+1];   //we have to return nth ugly number
        dp[1] = 1;  //1 is the first ugly number

        int[] pointers = new int[m];
        Arrays.fill(pointers , 1);  //all primes pointers points at one in begning

        for(int i = 2 ; i <= n ;i++){

            //1st loop to find min of all values
            long min = Integer.MAX_VALUE;
            for(int j = 0 ; j < m ; j++){
                long valf = (long)primes[j] * (long)dp[pointers[j]];

                min = Math.min(min , valf);
            }
            dp[i] = min;    //storing min value in dp

            //now incrementing indexes of pointers for primes which gave min value
            for(int j = 0 ; j < m ;j++){
                long valf = (long)primes[j] * (long)dp[pointers[j]];
                
                if(valf == min)
                pointers[j] ++;
            }
            
        }
        
        // for(int i = 0 ;i <= n ; i++)
        // System.out.print(dp[i] + " ");
        
        return (int)dp[n];
    }
}

https://leetcode.com/problems/super-ugly-number/

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