find max2 and min2. second largest and smalles numbers

PHOTO

Sun Jan 22 2023 23:07:33 GMT+0000 (Coordinated Universal Time)

#include <stdio.h>

int main() {
    int arr[10]={23,43,12,18,6,48,39,65,43,-3};
    int max = arr[0];
    int min = arr[0];
    int i;
    for(i=1;i<10;i++)
    {
        if(arr[i]>max)
            max=arr[i];
        if(arr[i]<min)
            min=arr[i];
    }
    printf("the maximum number of the array is %d ",max);
    printf("\nthe minimum number of the array is %d ",min);
    
    //find second maximium and minimum number of the array
    int max2=min;
    int min2=max;
    for(i=0;i<9;i++)
    {
        if(arr[i]!=max && arr[i]>max2)
        {
            max2=arr[i];
        }
        if(arr[i]!=min && arr[i]<min2)
        {
            min2=arr[i];
        }
    }
    printf("\nthe second maximum number is %d ",max2);
    printf("\nthe second minimum number is %d ",min2);
    return 0;
}

COPY

Save snippets that work from anywhere online with our extensions

Comments

array questions in class online

@Mohamedshariif

code in class online // array array quesitons in also class online find max and min of the array? find max2 and min2. second largest and smalles numbers

c - Where is PATH_MAX defined in Linux? - Stack Overflow

#include <linux/limits.h>

char current_path[PATH_MAX];

Old Traffic System

#include "SevSeg.h"
SevSeg sevseg;

int LEDRa = 33;
int LEDGa = 32;

int LEDRb = 23;
int LEDGb = 22;

int LEDRc = 50;
int LEDGc = 51;

int LEDRd = 42;
int LEDGd = 43;

int IRa1 = 44;
int IRa2 = 52;

int IRb1 = 49;
int IRb2 = 48;

int IRc1 = 35;
int IRc2 = 37;

int IRd1 = 47;
int IRd2 = 46;

int RoadATraffic[] = {0, 0};
int RoadBTraffic[] = {0, 0};
int RoadCTraffic[] = {0, 0};
int RoadDTraffic[] = {0, 0};

char jam[] = {'a', 'b', 'c', 'd', 'a', 'b', 'c', 'd', 'a', 'b', 'c', 'd', 'a', 'b', 'c', 'd'};

void setup() {
  pinMode (LEDRa, OUTPUT);
  pinMode (LEDGa, OUTPUT);

  pinMode (LEDRb, OUTPUT);
  pinMode (LEDGb, OUTPUT);

  pinMode (LEDRc, OUTPUT);
  pinMode (LEDGc, OUTPUT);

  pinMode (LEDRd, OUTPUT);
  pinMode (LEDGd, OUTPUT);

  pinMode (IRa1, INPUT);
  pinMode (IRa2, INPUT);

  pinMode (IRb1, INPUT);
  pinMode (IRb2, INPUT);

  pinMode (IRc1, INPUT);
  pinMode (IRc2, INPUT);

  pinMode (IRd1, INPUT);
  pinMode (IRd2, INPUT);

  byte numDigits = 2;
  byte digitPins[] = {11, 10};
  byte segmentPins[] = {9, 8, 6, 3, 4, 7, 2, 5};
  bool resistorsOnSegments = true;

  byte hardwareConfig = COMMON_CATHODE;
  sevseg.begin(hardwareConfig, numDigits, digitPins, segmentPins, resistorsOnSegments);
  sevseg.setBrightness(90);

  Serial.begin(9600); // open the serial port at 9600 bps:
}

static int counter = 5;
int jam_ind = 0;
int current_route = 0;

void loop() {
    //display();
    RoadATraffic[0] = (digitalRead (IRa1) != 1) ? ( 1 ) : ( 0 );
    RoadATraffic[1] = (digitalRead (IRa2) != 1) ? ( 1 ) : ( 0 );

    RoadBTraffic[0] = (digitalRead (IRb1) != 1) ? ( 1 ) : ( 0 );
    RoadBTraffic[1] = (digitalRead (IRb2) != 1) ? ( 1 ) : ( 0 );

    RoadCTraffic[0] = (digitalRead (IRc1) != 1) ? ( 1 ) : ( 0 );
    RoadCTraffic[1] = (digitalRead (IRc2) != 1) ? ( 1 ) : ( 0 );

    RoadDTraffic[0] = (digitalRead (IRd1) != 1) ? ( 1 ) : ( 0 );
    RoadDTraffic[1] = (digitalRead (IRd2) != 1) ? ( 1 ) : ( 0 );

    int sum1 = RoadATraffic[0] + RoadATraffic[1];
    int sum2 = RoadBTraffic[0] + RoadBTraffic[1];
    int sum3 = RoadCTraffic[0] + RoadCTraffic[1];
    int sum4 = RoadDTraffic[0] + RoadDTraffic[1];

    Serial.print(current_route);
    Serial.print('\n');
    Serial.print(jam_ind);
    Serial.print('\n');
    Serial.print('\n');

    change_route(jam[current_route]);
    display();
      
    if (sum1 >= sum2 && sum1 >= sum3 && sum1 >= sum4) {     // Road A Jam
      if (jam[current_route] == 'a' && counter == 1) {
        increase_jam_ind();
        jam[jam_ind] = 'a';
      } else if (jam[current_route] != 'a' && jam[jam_ind] != 'a') {
        increase_jam_ind();
        jam[jam_ind] = 'a';
      }
    }

    if (sum2 >= sum1 && sum2 >= sum3 && sum2 >= sum4) { // Road B Jam
      if (jam[current_route] == 'b' && counter == 1) {
        increase_jam_ind();
        jam[jam_ind] = 'b';
      } else if (jam[current_route] != 'b' && jam[jam_ind] != 'b') {
        increase_jam_ind();
        jam[jam_ind] = 'b';
      }
    }
    
    if (sum3 >= sum1 && sum3 >= sum2 && sum3 >= sum4) { // Road C Jam
      if (jam[current_route] == 'c' && counter == 1) {
        increase_jam_ind();
        jam[jam_ind] = 'c';
      } else if (jam[current_route] != 'c' && jam[jam_ind] != 'c') {
        increase_jam_ind();
        jam[jam_ind] = 'c';
      }
    }
      
    if (sum4 >= sum1 && sum4 >= sum2 && sum4 >= sum3) { // Road D Jam
      if (jam[current_route] == 'd' && counter == 1) {
        increase_jam_ind();
        jam[jam_ind] = 'd';
      } else if (jam[current_route] != 'd' && jam[jam_ind] != 'd') {
        increase_jam_ind();
        jam[jam_ind] = 'd';
      }
    }  
}

void display() {
  for (int h = 1; h<10000; h++){
    sevseg.setNumber(counter);
    sevseg.refreshDisplay();  
  }
  if (counter <= 0) {
    counter = 5;
    current_route++;
  }

  if (current_route > 15) { 
    current_route = 0;
  }
  
  counter--;
}

void change_route(char route) {
  switch (route) {
    case 'a':
      digitalWrite(LEDGa, HIGH);
      digitalWrite(LEDRa, LOW);
    
      digitalWrite(LEDGb, LOW);
      digitalWrite(LEDRb, HIGH);
    
      digitalWrite(LEDGc, LOW);
      digitalWrite(LEDRc, HIGH);
    
      digitalWrite(LEDGd, LOW);
      digitalWrite(LEDRd, HIGH);
      break;

    case 'b':
      digitalWrite(LEDGa, LOW);
      digitalWrite(LEDRa, HIGH);
    
      digitalWrite(LEDGb, HIGH);
      digitalWrite(LEDRb, LOW);
    
      digitalWrite(LEDGc, LOW);
      digitalWrite(LEDRc, HIGH);
    
      digitalWrite(LEDGd, LOW);
      digitalWrite(LEDRd, HIGH);
      break;

    case 'c':
      digitalWrite(LEDGa, LOW);
      digitalWrite(LEDRa, HIGH);
    
      digitalWrite(LEDGb, LOW);
      digitalWrite(LEDRb, HIGH);
    
      digitalWrite(LEDGc, HIGH);
      digitalWrite(LEDRc, LOW);
    
      digitalWrite(LEDGd, LOW);
      digitalWrite(LEDRd, HIGH);
      break;

    case 'd':
      digitalWrite(LEDGa, LOW);
      digitalWrite(LEDRa, HIGH);
    
      digitalWrite(LEDGb, LOW);
      digitalWrite(LEDRb, HIGH);
    
      digitalWrite(LEDGc, LOW);
      digitalWrite(LEDRc, HIGH);
    
      digitalWrite(LEDGd, HIGH);
      digitalWrite(LEDRd, LOW);
      break;
  }
}

void increase_jam_ind() {
  jam_ind++;
  if (jam_ind > 15) {
    jam_ind = 0;
  }
}

How to use the fgets() function in C

#include <stdio.h>

int main(){
  char str[20];
  
  fgets(str, 20, stdin); // read from stdin
  puts(str); // print read content out to stdout
  
  // open the file
  FILE *f = fopen("file.txt" , "r"); 
  
  // if there was an error
  if(f == NULL){
    perror("Error opening file"); // print error
    return(-1); 
  }
  // if there was no error
  else{ 
    fgets(str, 20, f); // read from file
    puts(str); // print read content out to stdout
  }
  
  fclose(f); // close file
  
  return(0);
}

Prying “.R” Script Files Away from Xcode (et al) on macOS | rud.is

sdk_path="/Library/Developer/CommandLineTools/SDKs"

#c #c++ #wrapper

Was ist ein Wrapper ? | C++ Community

class Wrapper
{
 private:
  CLib *lib;

 public:
  Wrapper() { lib = lib_init(); } // Lib initialisieren
  ~Wrapper() { lib_cleanup(&init); } // Lib freigeben

  std::string DoSomething() 
  { 
    char *cstr = lib_get_str(); // String anfordern (malloc!)

    std::string s = str;  // in std::string kopieren

    lib_free_str(cstr); // String freigeben (free)

    return s; // std::string zurückgeben. Alles easy.
  }
};

#c #c++ #wrapper

What is the meaning of a C++ Wrapper Class? - Stack Overflow

class int_ptr_wrapper
{
public:
    int_ptr_wrapper(int value = 0) :
    mInt(new int(value))
    {}

    // note! needs copy-constructor and copy-assignment operator!

    ~int_ptr_wrapper()
    {
        delete mInt;
    }

private:
    int* mInt;
};

LAB_EXAM

#include<stdio.h>
typedef struct student{
    int roll;
    char name[100];
    int marks[3];
}st;
void takeinput(st candidate[]){
     for(int i=0;i<5;i++){
        printf("\nFor student %d\n",i+1);
        printf("Enter the following details\n");
        printf("roll:");
        scanf("%d",&candidate[i].roll);
        printf("name:");
        scanf("%s",candidate[i].name);
        for(int j=0;j<3;j++){
            printf("marks in subject %d:",j+1);
            scanf("%d",&candidate[i].marks[j]);
        }
     }
}
void printinput(st candidate[]){
    printf("The details of all the students are as follows\n");
    for(int i=0;i<5;i++){
        printf("\nroll no:%d\nname:%s\n",candidate[i].roll,candidate[i].name);
        for(int j=0;j<3;j++){
            printf("marks in subject %d:%d\n",j+1,candidate[i].marks[j]);
        }
    }
}
void average_st_mks(st candidate[]){
    printf("Enter the serial number(1-5) of the student whose average marks to be known\n");
    int no;
    scanf("%d",&no);
    int sum=0;
    for(int i=0;i<3;i++) sum+=candidate[no-1].marks[i];
    float avg=(float)sum/3;
    printf("The average marks candidate bearing roll:%d is %.2f\n",candidate[no-1].roll,avg);
}
void average_subj_mks(st candidates[]){
    printf("Enter the serial number(1-3) of the subject whose average is to be known\n");
    int subject_number;
    scanf("%d",&subject_number);
    int sum=0;
    for(int i=0;i<5;i++){
        sum+=candidates[i].marks[subject_number-1];
    }
    float avg=(float)sum/5;
    printf("The average score of students in subject no:%d is %.2f\n",subject_number,avg);
}
void swap(st *candidate){
    printf("Enter the serial number(1-5) of student whose subject marks are to be swapped\n");
    int i;
    scanf("%d",&i);
    printf("Enter the serial number(1-3) of two subjects whose marks to be swapped\n");
    int a,b;
    scanf("%d%d",&a,&b);
    int temp=candidate[i-1].marks[a-1];
    candidate[i-1].marks[a-1]=candidate[i-1].marks[b-1];
    candidate[i-1].marks[b-1]=temp;
}
void print_mks_student(st candidate[]){
    printf("Enter the serial number(1-5) of the student you want to print marks\n");
    int n;
    scanf("%d",&n);
    for(int i=0;i<3;i++){
        printf("subject %d: %d mks\n",i+1,candidate[n-1].marks[i]);
    }
}
void upp_to_low(st candidate[]){
    printf("Enter the serial number(1-5) of student you want to convert name to lowercase\n");
    int n;
    scanf("%d",&n);
    int i=0;
    do{
        char ch=candidate[n-1].name[i];
        if(ch>=65 && ch<=90) candidate[n-1].name[i]=ch+32;
        i++;
    }while(candidate[n-1].name[i]!='\0');
    printf("student name changed to %s\n",candidate[n-1].name);
}
int main(){
    st candidate[5];
    int flag=1;
    char choice;
    do{
        printf("\nEnter the choice from the menu as per mentioned in the question paper\n");
        printf("The choice should be between a-g(lowercase)\nEnter any other character to stop the program\n");
        scanf(" %c",&choice);
        switch(choice){
        case 'a':takeinput(candidate);
        break;
        case 'b':printinput(candidate); 
        break;
        case 'c':average_st_mks(candidate);
        break;
        case 'd':average_subj_mks(candidate);
        break;
        case 'e':swap(candidate);
        break;
        case 'f':print_mks_student(candidate);
        break;
        case 'g':upp_to_low(candidate);
        break;
        default: flag=0;
        }
    }while(flag==1);
    return 0;
}

Debug Challenge!

#include<stdio.h>
#define take(n) scanf("%d",&n);
#define rep(i,a,b) for(int i=a;i<b;i++)
void add_10(int n){
    printf("Enter a number\n");
    int x;
    take(x);
    printf("%d+%d=%d\n",n,x,n+x);
}
void multiply_10(int n){
    printf("Enter a number\n");
    int x;
    take(x);
    printf("%d*%d=%d\n",n,x,n*x);
}

int main()
{
    int n=10;
    char choice;
    int flag=0;
    do{
        printf("Enter your choice either a or b, any other to exit\n");
        scanf("%c",&choice);
        switch(choice){
            case 'A':
            case 'a': add_10(n);
            break;
            case 'B':
            case 'b': multiply_10(n);
            break;
            default: flag=1;
        }
    }while(flag==0);
return 0;
}

C Program to Implement Queue Using Two Stacks - Sanfoundry

https://www.sanfoundry.com/c-program-implement-queue-using-two-stacks/

rectangle area calculator

#include <stdio.h>
int main()
{
	int lenght,bredth;
	int end;
	printf("what is the lenght of the rectangle \n");
	scanf("%d",&lenght);
	printf("what is the bredth of rectangle \n");
    scanf("%d",&bredth);
    printf("area of rectangle = %d \n",lenght*bredth);
    printf("Programe By Aaryan \n");
    printf("press any key to proseed");
    scanf("%d",&end);
	return 0;
}

KSA - Key Scheduling Algorithm

j = 0;
S = range(256)
for i in range(256):
    j = (j + S[i] + K[i%n]) % 256
    S[i], S[j] = S[j], S[i]

RC4 - Algoritmo central

i = 0
j = 0
for b in range(m):
    i = (i + 1) % 256
    j = (j + S[i]) % 256
    S[i], S[j] = S[j], S[i]
    KS[b] = S[(S[i] + S[j]) % 256]

Salsa20 función central

#define R(a,b) (((a) << (b)) | ((a) >> (32 - (b))))
void salsa20_word_specification(uint32 out[16],uint32 in[16])
{
    int i;
    uint32 x[16];
    for (i = 0;i < 16;++i) x[i] = in[i];
    for (i = 20;i > 0;i -= 2) {
        x[ 4] ^= R(x[ 0]+x[12], 7);  x[ 8] ^= R(x[ 4]+x[ 0], 9);
        x[12] ^= R(x[ 8]+x[ 4],13);  x[ 0] ^= R(x[12]+x[ 8],18);
        x[ 9] ^= R(x[ 5]+x[ 1], 7);  x[13] ^= R(x[ 9]+x[ 5], 9);
        x[ 1] ^= R(x[13]+x[ 9],13);  x[ 5] ^= R(x[ 1]+x[13],18);
        x[14] ^= R(x[10]+x[ 6], 7);  x[ 2] ^= R(x[14]+x[10], 9);
        x[ 6] ^= R(x[ 2]+x[14],13);  x[10] ^= R(x[ 6]+x[ 2],18);
        x[ 3] ^= R(x[15]+x[11], 7);  x[ 7] ^= R(x[ 3]+x[15], 9);
        x[11] ^= R(x[ 7]+x[ 3],13);  x[15] ^= R(x[11]+x[ 7],18);
        x[ 1] ^= R(x[ 0]+x[ 3], 7);  x[ 2] ^= R(x[ 1]+x[ 0], 9);
        x[ 3] ^= R(x[ 2]+x[ 1],13);  x[ 0] ^= R(x[ 3]+x[ 2],18);
        x[ 6] ^= R(x[ 5]+x[ 4], 7);  x[ 7] ^= R(x[ 6]+x[ 5], 9);
        x[ 4] ^= R(x[ 7]+x[ 6],13);  x[ 5] ^= R(x[ 4]+x[ 7],18);
        x[11] ^= R(x[10]+x[ 9], 7);  x[ 8] ^= R(x[11]+x[10], 9);
        x[ 9] ^= R(x[ 8]+x[11],13);  x[10] ^= R(x[ 9]+x[ 8],18);
        x[12] ^= R(x[15]+x[14], 7);  x[13] ^= R(x[12]+x[15], 9);
        x[14] ^= R(x[13]+x[12],13);  x[15] ^= R(x[14]+x[13],18);
    }
    for (i = 0;i < 16;++i) out[i] = x[i] + in[i];
}

Error de gets

#include <stdio.h>
int main () {
    char username[8];
    int allow = 0;
    printf external link("Enter your username, please: ");
    gets(username);
    if (grantAccess(username)) {
        allow = 1;
    }
    if (allow != 0) {
        privilegedAction();
    }
    return 0;
}

Error de tmp

#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
 
#define MY_TMP_FILE "/tmp/file.tmp"
 
 
int main(int argc, char* argv[])
{
    FILE * f;
    if (!access(MY_TMP_FILE, F_OK)) {
        printf external link("File exists!\n");
        return EXIT_FAILURE;
    }
    tmpFile = fopen(MY_TMP_FILE, "w");
 
    if (tmpFile == NULL) {
        return EXIT_FAILURE;
    }
 
    fputs("Some text...\n", tmpFile);
 
    fclose(tmpFile);
 
    return EXIT_SUCCESS;
}

find max2 and min2. second largest and smalles numbers

Save snippets that work from anywhere online with our extensions

Comments

More like this

array questions in class online

Browse more snippets >>

find max2 and min2. second largest and smalles numbers

Save snippets that work from anywhere online with our extensions

Comments

More like this

array questions in class online

Browse more snippets >>

Embed code snippet