// C program to add two numbers
#include <stdio.h>
  
int main()
{
    int A, B, sum = 0;
  
    // Ask user to enter the two numbers
    printf("Enter two numbers A and B : \n");
  
    // Read two numbers from the user || A = 2, B = 3
    scanf("%d%d", &A, &B);
  
    // Calculate the addition of A and B
    // using '+' operator
    sum = A + B;
  
    // Print the sum
    printf("Sum of A and B is: %d", sum);
  
    return 0;
}

def combinationSum2(candidates, target):
    res = []
    candidates.sort()
    
    def dfs(target, index, path):
        if target < 0:
            return  # backtracking
        if target == 0:
            res.append(path)
            return  # backtracking 
        for i in range(index, len(candidates)):
            if candidates[i] == candidates[i-1]:
                continue
            dfs(target-candidates[i], i+1, path+[candidates[i]])
            
    dfs(target, 0, [])
    return res

def combinationSum2(candidates, target):
    res = []
    candidates.sort()
    
    def dfs(target, index, path):
        if target < 0:
            return  # backtracking
        if target == 0:
            res.append(path)
            return 
        for i in range(index, len(candidates)):
            dfs(target-candidates[i], i, path+[candidates[i]])
            
    dfs(target, 0, [])
    return res

class Solution
{
    //Function to return sum of upper and lower triangles of a matrix.
    static ArrayList<Integer> sumTriangles(int matrix[][], int n)
    {
        ArrayList<Integer> list=new ArrayList<>();
        int sum1=0;
        int sum2=0;
        for(int g=0; g<matrix.length; g++){
            for(int i=0, j=g; j<matrix.length; i++,j++){
                sum1+=matrix[i][j];
            }
        }
        list.add(sum1);
        for(int g=0; g<matrix.length; g++){
            for(int i=g,j=0; i<matrix.length; i++,j++){
                sum2+=matrix[i][j];
            }
        }
        list.add(sum2);
        return list;
    }
}

Use Sum aggregate function with case statement as below, if you want sum of those t.value based on t.clock then do group by on that column so that you will get clock while sum of values.

select sum(case when  i.hostid='223344'   and t.itemid = '0223344' then t.value end) as FirstValue,sum(case when  i.hostid='112233' and t.itemid = '0112233' then t.value end) as SecondValue
from hosts h, items i,history_uint t
where i.hostid=h.hostid and t.itemid=i.itemid
If it is based on t.clock then

   select t.clock, sum(case when  i.hostid='223344'   and t.itemid = '0223344' then t.value end) as FirstValue,sum(case when  i.hostid='112233' and t.itemid = '0112233' then t.value end) as SecondValue
    from hosts h, items i,history_uint t
    where i.hostid=h.hostid and t.itemid=i.itemid
    group by t.clock
    0

You can try this below logic-

SELECT i.hostid,t.itemid,t.value as OneValues, t.clock as time
FROM hosts h 
INNER JOIN items i 
    ON i.hostid=h.hostid
    AND i.hostid IN ('223344','112233')
    AND i.itemid IN ('0223344','0112233')
INNER JOIN  history_uint t 
    ON t.itemid=i.itemid