check whether the reversed integer is also an Armstrong number

#include <iostream>
#include<cmath>
#include<ctime>
#include<string>
#include <iomanip>
#include <fstream>

using namespace std;

bool isArmstrong(int n);
int reversNumber(int n);
void isReversedArmstrong(int n);

int main()
{
	cout << "Enter first integer: ";
	int n1;
	cin >> n1;
	isReversedArmstrong(n1);
	

}

bool isArmstrong(int n)
{
	int temp = 0,armstrong, total = 0;
	armstrong = n;
	while (armstrong != 0)
	{
		temp = armstrong % 10;
		total += pow(temp, 3);
		armstrong /= 10;
	}
	if (total == n)
		return true;
	else
		return false;
 }
int reversNumber(int n)
{
	int reverse = 0, rem = 0;
	while (n != 0)
	{
		rem = n % 10;
		reverse = reverse * 10 + rem;
		n /= 10;
	}
	return reverse;
}
void isReversedArmstrong(int n)
{
	if (isArmstrong(n))
	{
		if(isArmstrong(reversNumber(n)))
			cout << "the Reversed "<< reversNumber(n)<<" number IS an Armstrong number ";
		else
			cout << "the Reversed " << reversNumber(n) << " number is NOT Armstrong number ";
	}
	else
		cout << "the number entered is NOT Armstrong number ";

}