Pointer cube

PHOTO EMBED

Sun Jun 09 2024 11:29:47 GMT+0000 (Coordinated Universal Time)

Saved by @meanaspotato #c #pointer

#include <stdio.h>

void cube(float* number);

int main(void)
{
	float x = 0.0f;

	printf("> ");
	scanf("%f", &x);

	// TODO: Call cube with x by reference...
	cube(&x);
	
	printf("x holds %f\n\n", x);

	return 0;
}

// TODO: Define cube function:
void cube(float* number)
{
    *number = (*number)*(*number)*(*number);
    
}
content_copyCOPY

Objective The exercise is designed to familiarize students with function prototypes, pointers, and arithmetic operations in C. Specifically, the task is to implement a function named cube that modifies a float value by reference, cubing the value it points to. Requirements Function Prototype: Declare a function prototype for cube that returns void and takes a single parameter: a pointer to a float. Function Definition: Define the cube function such that it cubes the value pointed to by its parameter. Main Function: The main function initializes a local float variable x to 0.0f. Prompt the user for a float value to store in x. Call the cube function, passing in the address of x. Print the new value of x. Code Standards: Your code should follow good programming standards, which include: Proper indentation and whitespace Meaningful variable names Effective commenting to explain the code Guidance In the function prototype for cube, ensure that you define the parameter as a pointer to a float. When calling cube in the main function, make sure you pass the variable x by reference, using the address-of operator &. For example: Input Result 5 > x holds 125.000000